Post a New Question

AP Calculus

posted by .

Find the total area enclosed by the graph of y=(e^sinx)*(cosx) and the x-axis from x=0 to x=pi

I got .0563331993 but when I checked it graphically I got 3.22765

  • AP Calculus -

    You need to integrate the y function from 0 to pi. The indefinite integral is e^sinx

    Its value is 1 at x=pi and 1 at x = 0.

    The definite integral is therefore zero.
    The area from 0 to pi/2 is the same as the area from pi/2 to pi, but the sign changes when the curve goes below the x axis.

    if you don't count area below the x axis as negative, the area you should get is 2(e -1) = 3.437

  • AP Calculus -

    Yep, the graph looks kind of like a squiggly line with equal area above and below the X axis. If you're looking for the total enclosed area, you want to multiply the integral from zero to pi/2 by 2. If you're actually taking the integral though (you're concerned about the sign of the area not just the absolute value), you would get zero. Your calculator will report something like .0563331993 because it is approximating the answer.

    Check out Ignition Tutoring if you want more homework help :)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question