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March 29, 2017

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A child sits on a rotating merry-go-round, 2.19 m from its center. If the speed of the child is 2.32 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?

  • Physics - ,

    ΣFy=0
    Normal Force = mass*gravity
    N=m*g

    ΣFx=ma
    Force of Friction = mass*velocity^2/radius
    F=m*v^2/r
    Force of Friction = Coefficient of static friction*Normal force
    F=Us*N

    So...
    Us*m*g=m*v^2/r
    Us=v^2/(r*g)

  • Physics - ,

    58?

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