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July 23, 2014

July 23, 2014

Posted by **Victoria** on Sunday, March 6, 2011 at 12:13pm.

- trig -
**Henry**, Sunday, March 6, 2011 at 8:49pmB(-3,4), Q2.

r^2 = (-3)^2 + 4^2 = 25,

r = 5.

sinAr = Y/r= 4 / 5 = 0.8,

Ar = 53.1deg = reference angle.

sinAr = Y/r = 4 / 5 = 0.80,

Since the angle is in Q2,the angle

calculated is actually the ref angle

which has the same trig ratios as the

actual angle. The actual angle is:

A = 180 - Ar = 180 - 53.1 = 126.9deg.

sin126.9 = 0.8 = sin53.1.

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