posted by ike on .
a uniform electric field of magnitude 2.5*10^4, makes an angle of 27 with a plane surface area of 0.0133m^2.what is the electric flux through the surface.
Assuming that the field strength dimensions are Volts per meter, and that the 27 degrees is the angle between the E field direction and the surface (rather than the normal to the surface), then the electric flux is:
Area * sin27 * (E field strength)
The area must be in square meters. You need to be more careful stating what the dimensions are when you do physics calculations.