Homework Help: physics

Posted by kik on Sunday, March 6, 2011 at 7:40am.

A 5-g marble, released form rest, was allowed to roll on a ramp whose lower end is 25 cm from the floor. When it left the ramp, it behaved like a body in projectile motion. What was the horizontal velocity of this marble when it left the ramp? With what momentum did it leave the ramp?

physics - bobpursley, Sunday, March 6, 2011 at 8:28am
You have to know something about the ramp to answer these questions.
physics - Anonymous, Thursday, March 10, 2011 at 6:33am
M= 1525g= 1.525 kg
W= 14.95 N

Force required to start the block into motion:
F= 0.685(9.8)= 6.71N

Force to maintain motion:
F= 0.512(9.8)= 5.02N

Compute 痘 and 盜:
痘 = 5.02/14.95 = 0.34 盜 = 6.72/14.95 = 0.45

Answer this Question

Related Questions

Physics - I've got a question: Imagine this scenario where someone releases ...
Physics please help!! - A 1.94 kg solid sphere (radius = 0.105 m) is released ...
physics help 3 please!! - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) ...
PHYSICS 2 - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) is released ...
Physics - Circular motion - A marble of mass m is placed on top of a bowling ...
Physics - A 14.6-g marble is dropped from rest onto the floor 1.23 m below. If ...
AP Physics - A small solid marble of mass m and radius r will roll without ...
Physics - A mass sits at the top of a 2 meter long ramp inclined at an angle of ...
physics - As shown in the figure below, a 2.25-kg block is released from rest on...
physics - A 25.1 g marble moving to the right at 22.9 cm/s overtakes and ...

For Further Reading

First Name:
School Subject:
Answer: