Posted by **Tori** on Saturday, March 5, 2011 at 7:17pm.

A hollow cone has height 5 feet and base diameter 4 feet. The vertex of the cone is pointed down so that it can serve as a container. Water is poured into the cone at the rate 3/2 cubic feet per second. At what rate (in feet per second) is the depth of the water increasing when the depth of the water is 3 feet?

- calculus -
**Damon**, Saturday, March 5, 2011 at 7:22pm
Find the area of the surface of the water when water is 3 feet from the tip (A =pi r^2) where r = (2/5)(3)

dh (A) = dV

dh/dt = (1/A)(dV/dt)

but dV/dt is given, 3/2 ft^3/s

- calculus -
**Tori**, Saturday, March 5, 2011 at 7:26pm
25/24pi....I think is the answer

- calculus -
**Damon**, Saturday, March 5, 2011 at 7:41pm
r = 6/5

pi r^2 = pi (36/25)

dh/dt = 25/(36pi) * 3/2

= 25 /24pi

agree

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