Posted by **Chris** on Saturday, March 5, 2011 at 6:49pm.

A triangle has sides of lengths 20, 28, and 32. A similiar triangle has a side of length 15 and another of length 24. How long is the third side of this triangle?

- algebra -
**jai**, Saturday, March 5, 2011 at 7:15pm
for similar triangles, the ratio of the sides of the first triangle is equal to the ration of the corresponding sides of the second triangle,, like:

let h1 = height of 1st triangle

let h2 = height of 2nd triangle

let b1 = base of 1st triangle

let b2 = base of 2nd triangle

therefore, if they are similar triangles,

(h1)/(b1) = (h2)/(b2)

thus in the question, we can write:

let x = third side

20/15 = 32/24 = 28/x

simplifying:

4/3 = 28/x

solving for the third side,

x = 21

hope this helps~ :)

- algebra -
**Damon**, Saturday, March 5, 2011 at 7:16pm
20/15 = 4/3

28/24 = nope

32/24 = 4/3 yes

so

20 --> 15

32 --> 24

28(3/4) = 21

so

20 , 28 , 32

--->

15 , 21 , 24

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