Saturday

October 25, 2014

October 25, 2014

Posted by **applebottom** on Saturday, March 5, 2011 at 5:20pm.

- Calculus -
**Reiny**, Saturday, March 5, 2011 at 5:57pmDid you make a sketch?

Your intersectio points are not "nice" making for messy arithmetic.

the curve and y=4 intersect at (64/3 , 4)

the curve and the line x+2y=4 intersect at appr (1.73, 1.14) and the line x+2y=4 intersects y = 4 at ((-4,4)

So you have to find it in two parts:

Left section:

Area = [integral] (4 - (-1/2)x + 2) ) dx from -4 to 1.73

= (4x + (1/4)x^2 - 2x ) dx from -4 to 1.73

= you do the arithmetic

Right section:

Area = Area = [integral] (4 - (1/2)(3x)^(1/2) ) dx from 1.73 to 64/3

= (4x - (1/9)(3x)^(3/2) ) from 1.73 to 64/3

= you do the arithmetic

add up the two parts.

**Answer this Question**

**Related Questions**

math - i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4

Math: Need Answer to study for a quizz. Help ASAP - Estimate the area under the...

Calculus - Finding area under a curve From [1,3] 2x^2 -4x +1

Calculus - Integrals: When we solve for area under a curve, we must consider ...

Calculus - Find the area cut off by x+y=3 from xy=2. I have proceeded as under: ...

Calculus - what is Trapezoidal rule? How does it work in finding the area under ...

Stats - Need help finding the area under the normal curve between z = -1.0 and z...

Math - Estimate the are under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph ...

Calculus ll - Improper Integrals - Find the area of the curve y = 1/(x^3) from x...

calculus - Compute the area of the region in the fi…rst quadrant bounded on...