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November 26, 2014

November 26, 2014

Posted by **ike** on Saturday, March 5, 2011 at 3:32pm.

- not a radial distance r? -
**Damon**, Saturday, March 5, 2011 at 4:06pmI suspect a typo here.

Yes, use Gauss's law if the length is great compared to the distance r

here L = 5 and r = 0.1

Area of cylinder around wire at distance r is 2 pi r L

integral of E coming out of surface = charge inside /eo

so

2 pi r L E = 5*10^-8 L /eo

so

E = 5*10^-8 /(2 pi eo) = 10*10^-8 /(4 pi eo)

= 10^-7 k

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