Posted by **emily** on Saturday, March 5, 2011 at 2:39pm.

if a 100g sample of water at 60.0 C is added to a 100.0 g sample of water at 10.0 C, determine the final temperature of the water. Assume no heat is lost to the surroundings

- Chemistry -
**Danica Marie**, Monday, October 3, 2016 at 9:43am
The equation to be used for the problem is mcΔT = mcΔT.

From the given problem, we need to determine whether the heat is absorbed or evolved. When heat is absorbed, the sign is positive, and when heat is evolved, it is negative; therefore +q = -q, due to the reason then when the 100g of sample at 60.0C was added, it absorbed heat while the 100.0g sample of water at 10.0C evolved the heat towards the previous sample.

Applying the equation with the proper signs, we get mcΔT = -mcΔT, the specific heat of water is cancelled out right away.

Required: Final Temperature (T2)

mcΔT = (1)

-mcΔT = (2)

(1) m = 100.00g

T2-60.0C

(2) m = 100.00g

T2-10.0C

(100g) (T2-60.0C) = -(100g) (T2-10.0C)

Multiply the mass with the (T2-T1) equation.

100gT2 - 6000C = -100gT2 - 1000C

Transpose the values.

100gT2+100gT2 = 6000C - 1000C

200gT2 = 5000C

T2 = 5000C/200g

T2 = 25C.

## Answer This Question

## Related Questions

- Chemistry - A 271-g sample of nickel at 94.1°C is placed in 100.0 mL of water (...
- chemistry - a 100g sample of wate at 90oC is added to a 500g sample of water at ...
- chemistry - how would i calculate; a 50g sample of water at 100 degrees is ...
- Chemistry - A 100g sample of water absorbs 308kJ of heat. If the water was ...
- chemistry - A 275-g. sample of nickel at 100 degrees C is placed in 100 g. of ...
- science - 4. A 70.0 g sample of water at 95.00°C is mixed with 50.0 g of water ...
- Chemistry - My Chem professor is out for the weekend and I'm confused about what...
- science - A 30.0 g sample of water at 280. K is mixed with 50.0 g of water at ...
- chemistry - What will be the final temperature of the water in an insulated ...
- Chemistry - A 5.80 g sample of SiH4 and an excess of oxygen were placed in a ...

More Related Questions