A 5.10-g sample of iron is heated from 36.0 C to 75.0 C. The amount of energy required is 89.5 J. the specific heat capacity of the sample of iron is?
0.450J/T C
To find the specific heat capacity of the sample of iron, we can use the formula:
Q = mcΔT
Where:
Q = amount of energy (in Joules)
m = mass of the sample (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)
Given:
Q = 89.5 J
m = 5.10 g
ΔT = 75.0°C - 36.0°C = 39.0°C
Plugging in the given values into the formula:
89.5 J = (5.10 g) x c x 39.0°C
To find c, we can rearrange the equation:
c = 89.5 J / ((5.10 g) x 39.0°C)
Calculating the value:
c = 89.5 J / (199.5 g°C)
c = 0.448 J/g°C
Therefore, the specific heat capacity of the sample of iron is 0.448 J/g°C.