A 5.10-g sample of iron is heated from 36.0 C to 75.0 C. The amount of energy required is 89.5 J. the specific heat capacity of the sample of iron is?

0.450J/T C

To find the specific heat capacity of the sample of iron, we can use the formula:

Q = mcΔT

Where:
Q = amount of energy (in Joules)
m = mass of the sample (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)

Given:
Q = 89.5 J
m = 5.10 g
ΔT = 75.0°C - 36.0°C = 39.0°C

Plugging in the given values into the formula:

89.5 J = (5.10 g) x c x 39.0°C

To find c, we can rearrange the equation:

c = 89.5 J / ((5.10 g) x 39.0°C)

Calculating the value:
c = 89.5 J / (199.5 g°C)

c = 0.448 J/g°C

Therefore, the specific heat capacity of the sample of iron is 0.448 J/g°C.