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April 19, 2014

April 19, 2014

Posted by **YANA** on Friday, March 4, 2011 at 10:53pm.

- PHYSICS -
**YANA**, Friday, March 4, 2011 at 11:16pmThe average power dissipated in a 47-Ù resistor is 5.9 W. What is the peak value I0 of the ac current in the resistor?

- PHYSICS -
**drwls**, Saturday, March 5, 2011 at 12:09amAverage power is half the product of peak voltage and peak current.

For your second question

Avg. Power = (1/2)Io^2*R

Solve for Io

Peak voltages and currents are usually not used in AC calculations; instead, r.m.s. (root mean square) values are used. They are 0.707 (1/sqrt2) times the peak value

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