Posted by Ellen on Friday, March 4, 2011 at 12:29pm.
Is 9.832 m/s^2 the value at the North Pole? You should have made that clear.
Formulas to use are:
Period: P = 2 pi sqrt(L/g)
frequency: f = 1/P
You do the numbers.
My teacher didn't specify if 9.821 m/s^2 is the value of the North Pole. We don't have class this week because of Spring Break and it's due the morning we get back, so I can't ask him any questions. But I got C through F now, thank you!
Related Questions
physics - calculate the period and frequency of a 3.500 m long pendulum at the ...
physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
physics - A simple pendulum consists of a ball of mass 5.39 kg hanging from a ...
physics - A pendulum clock can be approximated as a simple pendulum of length 1....
physics7 - A 81.0-kg (179 lb) boxer has his first match in the Canal Zone (g = 9...
physics - a simple pendulum has a period of 4.2sec. when the pendulum is ...
physics - Suppose a simple pendulum is used to measure the acceleration due to ...
Physics - A(n) 95.7 kg boxer has his first match in the Canal Zone with ...
Physics - A(n) 95.7 kg boxer has his first match in the Canal Zone with ...
For Further Reading