Post a New Question

Posted by Anna on Friday, March 4, 2011 at 2:01am.

I need help to solve this problem by factoring: 2x^2-x-3=0

(2x-3)(x+1)

2x^2-x-3=0 first step: 2*2x^-x-3=0 4x^-x-3=0 (4x^-4x)+(3x-3)=0 4x(x-1)+3(x-1) (4x+3)(x-1)=0 (4x+3)=0 (x-1)=0 4x+3=0 X-1=0 -3 -3 -1 -1 4x=-3 x=-1 x=-3/4 Therefore, X=(-3/4, -1)

More Related Questions