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Two loudspeakers are 2.54 m apart. A person stands 3.04 m from one speaker and 3.50 m from the other. What is the lowest frequency at which destructive interference (sound cancellation) will occur at this point?

  • physics -

    distances have to be one half wavelength apart.

    3.04-3.50=1/2 lambda

    lambda= .92meter check that, so

    f= velocitysound/.92

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