February 26, 2017

Homework Help: physics

Posted by Trace on Thursday, March 3, 2011 at 6:48pm.

The length of the auditory canal in humans averages about 2.5 cm. What is the second lowest
standing wave frequency for a pipe of this length open at one end? Use 345 m/s for the speed of

I know that 4L=lambda, so lambda= 10cm.
I know that f=v/lambda, so f=3450 Hz.

But is that the lowest standing frequency? And how do I find the second lowest? Thanks

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