posted by Trace on .
The length of the auditory canal in humans averages about 2.5 cm. What is the second lowest
standing wave frequency for a pipe of this length open at one end? Use 345 m/s for the speed of
I know that 4L=lambda, so lambda= 10cm.
I know that f=v/lambda, so f=3450 Hz.
But is that the lowest standing frequency? And how do I find the second lowest? Thanks