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November 28, 2014

November 28, 2014

Posted by **Jackster** on Wednesday, March 2, 2011 at 9:07pm.

a + bi. -8-8i/1+2i

- math -
**MathMate**, Wednesday, March 2, 2011 at 9:57pmThis can be accomplished by multiplying numerator and denominator by the complex conjugate of the denominator, 1-2i.

(-8-8i)*(1-2i) / ((1+2i)(1-2i))

8(-1-2 -i+2i) /(1-4i²)

8(i-3)/5

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