posted by Dan on .
Calculate the mass of sodium bicarbonate needed to neutralize 3.0 mL of 3.0 M HCl. Show your work.
NaHCO3 + HCl ==> NaCl + H2O + CO2
moles HCl = M x L = ??
moles NaHCO3 (use the coefficients in the balanced equation) = moles HCl
moles NaHCO3 = grams/molar mass. Solve for grams.