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July 26, 2014

July 26, 2014

Posted by **Bethany** on Wednesday, March 2, 2011 at 3:20pm.

2. Find an equation of the line that passes through the point (9,7) and is perpendicular to the line 5x+3y-4=0

- Calculus - question incomplete -
**MathMate**, Wednesday, March 2, 2011 at 3:57pm1. "the function" is not specified.

2.

The equation perpendicular to the line

L: 5x+3y-4=0

is

L1 : 3x-5y+k=0

where k is a constant to be determined.

The equation of L1 is obtained by interchanging the coefficients of x and y,*and*changing the sign of x*or*y.

The constant k can be determined by the fact that L1 passes through (9,7).

3(9)-5(7)+k=0

k=35-27=8

So

L1: 3x-5y+8=0

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