Posted by Bethany on Wednesday, March 2, 2011 at 3:20pm.
1. "the function" is not specified.
2.
The equation perpendicular to the line
L: 5x+3y-4=0
is
L1 : 3x-5y+k=0
where k is a constant to be determined.
The equation of L1 is obtained by interchanging the coefficients of x and y, and changing the sign of x or y.
The constant k can be determined by the fact that L1 passes through (9,7).
3(9)-5(7)+k=0
k=35-27=8
So
L1: 3x-5y+8=0
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