Posted by karim on Wednesday, March 2, 2011 at 3:10pm.
Let B = the buoyancy force and M = the initial total mass. Let m be the ballast mass released
M g - B = M*1.2 m/s^2
(M-m)g -B = -M*1.2 m/s^2
Solve for m.
m g = M*2.4m/s^2
m/M = 2.4/g
m = 0.245 M = 49 kg
Related Questions
physics - A hot-air balloon of mass 200 kg is descending vertically with ...
Physics - A research balloon of total mass 445 kg is descending vertically with ...
Physics - A research balloon of total mass 200 kg is descending vertically with ...
physics - Several people are riding in a hot-air balloon. The combined mass of ...
physics - Several people are riding in a hot-air balloon. The combined mass of ...
PHYSICS - Several people are riding in a hot-air balloon. The combined mass of ...
physics - A balloon of total mass 840 kg is rising vertically with constant ...
physics - a hot air balloon rise above the ground, accelerating upwards at a ...
Physics - A hot-air balloon has a total mass of 720 kg. It accelerates downwards...
physics - A recreational (open) hot air balloon (i.e., Pinside is approximately ...
For Further Reading