precalculus
posted by josh on .
A bacteria culture initially contains 1500 bacteria and doubles every half hour.
a) Find an expression for the number of bacteria after t hours.
Q(t)=
b) The number of bacteria after 20 minutes is (the answer must be an integer)
c) The number of bacteria after 9 hours is

(a) 1500*2^(t/0.5) = 1500*2^(2t)
(b) 1500*2^(2*20/60) = ?
(c) 1500*2^(2*9) = ?