Posted by Amu on Wednesday, March 2, 2011 at 12:18pm.
Qadratic equation;
y=ax^2+bx+c
In your case:
a=3 b=-1 c=-4
Discriminant: D=b^2-4ac
D=(-1)^-4*3*(-4)
D=1+48
D=49
When D>0 equation hawe two real solutions.
x1=[-b-sqroot(b^2-4ac)]/2a
x1=[-(-1)-sqroot(49)]/(2*3)
x1=(1-7)/6
x1= -6/6
x1= -1
x2=[-b+sqroot(b^2-4ac)]/2a
x2=[-(-1)+sqroot(49)]/(2*3)
x2=(1+7)/6
x2=8/6
x2=(2*4)/(2*3)
x2=4/3
x2=1.333333
For more information in google type: quadratic equation
When you see lis of results go to:
Quadratic equation-Wikipedia,the free encyclopedia
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