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April 20, 2014

April 20, 2014

Posted by **zane** on Wednesday, March 2, 2011 at 1:21am.

f(x)= 1

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6x^2

- calculus -
**agrin04**, Wednesday, March 2, 2011 at 4:34amf(x) = 1/(6x^2) = (1/6)x^(-2)

f'(x) = (-1/3)x^(-3)

f''(x) = x^(-4) = 1/x^4

As to answer question b, just change x with 3 and calculate the result

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