Posted by zane on Wednesday, March 2, 2011 at 1:21am.
f(x) = 1/(6x^2) = (1/6)x^(-2)
f'(x) = (-1/3)x^(-3)
f''(x) = x^(-4) = 1/x^4
As to answer question b, just change x with 3 and calculate the result
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