Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning.
Thanks
Use the formula
Q = M C * (delta T), with
Q (the heat) = 900 cal
M (the mass) = 400 g
C (the specific heat) = 0.092 cal/(g*C)
Solve for the temperature change, delta T in degrees C)
delta T = Q/(M*C)
To find the temperature change of the copper object, we can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat transferred,
m is the mass of the object,
c is the specific heat of the substance, and
ΔT is the change in temperature.
We are given:
- The mass of the copper object, which is 400 grams (m = 400 g),
- The specific heat of copper, which is 0.092 cal/g/°C (c = 0.092 cal/g/°C),
- The amount of heat transferred to the object, which is 900 calories (Q = 900 cal).
We need to solve for the change in temperature (ΔT).
Rearranging the equation, we get:
ΔT = Q / (m * c)
Substituting the given values, we have:
ΔT = 900 cal / (400 g * 0.092 cal/g/°C)
Now let's calculate:
ΔT = 900 cal / (36.8 cal/°C)
Dividing 900 by 36.8, we get:
ΔT ≈ 24.46 °C
Therefore, the temperature change of the copper object is approximately 24.46 degrees Celsius.