Post a New Question

Physics

posted by on .

Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning.

Thanks

  • Physics - ,

    Use the formula

    Q = M C * (delta T), with

    Q (the heat) = 900 cal
    M (the mass) = 400 g
    C (the specific heat) = 0.092 cal/(g*C)

    Solve for the temperature change, delta T in degrees C)

    delta T = Q/(M*C)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question