Posted by A on .
Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning.
Thanks

Physics 
drwls,
Use the formula
Q = M C * (delta T), with
Q (the heat) = 900 cal
M (the mass) = 400 g
C (the specific heat) = 0.092 cal/(g*C)
Solve for the temperature change, delta T in degrees C)
delta T = Q/(M*C)