Homework Help: Physics

Posted by A on Wednesday, March 2, 2011 at 12:54am.

Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning.

Thanks

Physics - drwls, Wednesday, March 2, 2011 at 1:04am
Use the formula

Q = M C * (delta T), with

Q (the heat) = 900 cal
M (the mass) = 400 g
C (the specific heat) = 0.092 cal/(g*C)

Solve for the temperature change, delta T in degrees C)

delta T = Q/(M*C)

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