Using equation: 2Fe(OH)3 + 3H2SO4 -> Fe2(SO4)3 + 6H2O
Question: How many molecules of H2O can be made from 9.21 x 10^22 molecules of H2SO4?
Here is an example of a stoichiometry problem. Just follow the steps. Convert molecules to moles this way.
molecules/6.022E23 = moles.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of molecules of H2O that can be made from 9.21 x 10^22 molecules of H2SO4, we need to use the balanced chemical equation provided:
2Fe(OH)3 + 3H2SO4 -> Fe2(SO4)3 + 6H2O
From the equation, we can see that the stoichiometric ratio between H2SO4 and H2O is 3:6. This means that for every 3 molecules of H2SO4, 6 molecules of H2O are produced.
To solve the problem, we can set up a proportion using the stoichiometric ratio:
3 H2SO4 / 6 H2O = (9.21 x 10^22 molecules of H2SO4) / X molecules of H2O
Cross-multiplying, we get:
3 * X = 6 * (9.21 x 10^22)
3X = 55.26 x 10^22
X = 18.42 x 10^22
Therefore, 9.21 x 10^22 molecules of H2SO4 can produce 18.42 x 10^22 molecules of H2O.