math

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Last year's computer model is on sale for \$799. You can add more memory to the computer. Each chip of 8 megabytes of memory costs \$25. How many megabytes of memory can you add if you have at most \$1,000 to spend.

• math - ,

= 1000-799
= \$201
Number of 8-MB chips \$201 can buy
= \$201/25
= 8 chips.
= 8*8Mb
= 64 Mb.

Note: assumes no tax payable

• PreAlgebra - ,

AT MOST signifies that you must write and inequality to solve this problem. AT MOST signifies to write the symbol "less than or equal to". <
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First write down what you know:
- You will spend \$1,000 at most
- The computer's initial cost is \$799
- Each chip contains 8 megabytes (MB)
- Each chips costs \$25
- \$1,000 - \$799 will give you how much money you will have left over

Now let's solve:
Let x represent the amount of megabytes you can add

\$1,000 - \$799 (gives you the amount of money you have left over to buy extra memory) = \$201

\$201/\$25 (gives you the number of chips you can buy) = 8

8(8) (gives you the number of megabytes you can buy - the answer!! ;D) = 64

The inequality with steps:
1,000 - 799
8( -------------- ) < x
25 ---

201
8( -------------- ) < x
25 ---

8(8) < x
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64 < x
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