Posted by Amy on Tuesday, March 1, 2011 at 9:42pm.
are those degrees ?
I will assume you are familiar with the basic identities.
1 + tan^2 (5°) - csc^2 (85)
= sec^2 (5) - csc^2(85
but sec Ø = csc(90-Ø)
so sec(5) = csc(85)
so continuing from above
= csc^2(85) - csc^2(85)
0
Correct if you work in degrees.
For details, see response:
http://www.jiskha.com/display.cgi?id=1299028595
tan 5=sin5/cos5=cos85/sin85
now, since they are the same angles, I will call that angle T
1+cos^2t/sin^t -1/sin^2t=
(sin^2+cos^2 -1)/sin^2t=
0
check that.
yes, they are degrees, thank you soo much!
geepers, three folks knew how to do it. I bet millions of others have laboured thru it also.
And all within one minute of each other !
Related Questions
MATH PLEASE HELP - 1 + tan^2 (5) - csc^2 (85) = ? Would this equal 0 could ...
Precalc Please Help - 1 + tan^2 (5) - csc^2 (85) = ? Would this equal 0 could ...
more trig.... how fun!!!! - if you can't help me with my first question hopw...
trig - (3 tan^2x-1)(tan^2-3)= 0 can someone please explain how to do this ...
trigonometry repost - Reduce (csc^2 x - sec^2 X) to an expression containing ...
math pre-calc h - It says which expressiion is equivalent to sec T + csc T / 1+...
Math - Trig - I'm trying to verify these trigonometric identities. 1. 1 / [...
Math - cos(tan + cot) = csc only simplify one side to equal csc so far I got ...
math - Jane is taking a class and asks you to help her figure out what her last ...
Pre Calculus. - Can someone check my answers please!!! Simplify (tan ^2 theta ...
For Further Reading
