Posted by **A** on Tuesday, March 1, 2011 at 8:25pm.

Please help!

Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning. Do not use algebra

Thanks!

- Physics -
**bobpursley**, Tuesday, March 1, 2011 at 9:55pm
900cal=400grams*.092cal/C*delatTemp

solve for DeltaTemp.

Do not use algebra? You have to be kidding. You could estimate it, 400x.1=40, and 400/40 is about 10C.

- Physics -
**bobpursley**, Tuesday, March 1, 2011 at 9:58pm
oops, the danger of estimated in the head.

900/40 is about 23C

Use algebra, and a calculator.

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