A basketball team scored 48 baskets in 1 game. Each basket was worth one or two points. If the team scored 84 points, how many one- point and two-point baskets did it score?

Let's assume the number of one-point baskets scored as x and the number of two-point baskets scored as y.

The total number of baskets can be calculated by summing the one-point and two-point baskets:
x + y = 48 (equation 1)

The total points can be calculated by multiplying the number of one-point baskets by 1 and the number of two-point baskets by 2, then summing them up:
1x + 2y = 84 (equation 2)

We now have a system of equations:
x + y = 48 (equation 1)
1x + 2y = 84 (equation 2)

To solve this system of equations, let's multiply equation 1 by 2:
2x + 2y = 96 (equation 3)

Now we can subtract equation 2 from equation 3:
(2x + 2y) - (1x + 2y) = 96 - 84
2x - x + 2y - 2y = 12
x = 12

So, the number of one-point baskets scored is 12.

Substituting this value back into equation 1, we can find the number of two-point baskets:
12 + y = 48
y = 48 - 12
y = 36

Therefore, the team scored 12 one-point baskets and 36 two-point baskets.

To solve this problem, we need to set up a system of equations. Let's assume that the team scored x one-point baskets and y two-point baskets.

Since each one-point basket is worth one point, the total number of points from one-point baskets is x.

And since each two-point basket is worth two points, the total number of points from two-point baskets is 2y.

We are given that the team scored 48 baskets in total. Therefore, we can write the equation:
x + y = 48 ----(1)

We are also given that the team scored a total of 84 points. Therefore, we can write the equation:
x + 2y = 84 ----(2)

Now we have a system of two equations with two variables. We can solve this system to find the values of x and y.

One way to solve this system is by using the method of substitution. We can solve equation (1) for x in terms of y:
x = 48 - y

Now we substitute this value of x into equation (2):
48 - y + 2y = 84

Simplifying:
48 + y = 84
y = 84 - 48
y = 36

Now we substitute the value of y back into equation (1) to find x:
x + 36 = 48
x = 48 - 36
x = 12

So the team scored 12 one-point baskets and 36 two-point baskets.

Let x = one-point baskets and 48-x = two-point baskets.

X + 2(48-x) = 84

Solve for x and then 48 - x.

i have no clue so ask ur teacher