2Fe(OH)3 + 3H2SO4 -> Fe2(SO4)3 + 6H2)

Question: How many molecules of H2O can be made from 9.21 x 10^22 molecules of H2SO4?

if you have molecules of nitrogen, how many liters of nitrogen gas are present

To determine how many molecules of H2O can be made from a given number of molecules of H2SO4, we need to use the balanced chemical equation and stoichiometry.

The balanced chemical equation is: 2Fe(OH)3 + 3H2SO4 -> Fe2(SO4)3 + 6H2O

From the equation, we can see that 3 molecules of H2SO4 produce 6 molecules of H2O. This means that the stoichiometric ratio between H2SO4 and H2O is 3:6, or simplifying it further, 1:2.

Now, we can set up a proportion to solve for the number of molecules of H2O. Let's call the number of molecules of H2SO4 "x" and the number of molecules of H2O "y".

Using the proportion:

(3 molecules of H2SO4 / 2 molecules of H2O) = (x molecules of H2SO4 / y molecules of H2O)

By cross-multiplying, we get:

3y = 2x

Now, we can substitute the given value: 9.21 x 10^22 molecules of H2SO4 = x

Solving for y, we have:

3y = 2(9.21 x 10^22)
y = (2/3)(9.21 x 10^22)
y = 6.14 x 10^22

Therefore, 6.14 x 10^22 molecules of H2O can be made from 9.21 x 10^22 molecules of H2SO4.