A 1.04L sample of gas at 759 mm Hg pressure is expanded until its volume is 2.24L. what is the pressure in the expanded gas sample (at constant temp.)
(P1V1) = (P2V2)
To determine the pressure in the expanded gas sample, we can use the combined gas law equation, which relates the initial and final conditions of a gas sample. The combined gas law equation is given as:
(P1 * V1) / T1 = (P2 * V2) / T2
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures. In this case, we are assuming the temperature remains constant, so T1 = T2.
Given:
Initial pressure (P1) = 759 mm Hg
Initial volume (V1) = 1.04 L
Final volume (V2) = 2.24 L
We need to find the final pressure (P2). Since the temperature is constant, we can rewrite the combined gas law equation as:
(P1 * V1) = (P2 * V2)
Now, let's substitute the known values into the equation:
(759 mm Hg * 1.04 L) = (P2 * 2.24 L)
Now, solve for P2 by rearranging the equation:
P2 = (759 mm Hg * 1.04 L) / (2.24 L)
P2 ≈ 350.67 mm Hg
Therefore, the pressure in the expanded gas sample (at constant temperature) is approximately 350.67 mm Hg.