a plastic container witha mass of 30 grams gains 1,140 joules of heat if the tempreature of the container increases 20 degrees celcius what is the specific heat of the plastic in the container

q = mass x specific heat x delta T.

To find the specific heat of the plastic in the container, you can use the formula:

Q = mcΔT

where:
Q = heat energy gained by the plastic container (in joules)
m = mass of the plastic container (in grams)
c = specific heat capacity of the plastic (in joules/gram °C)
ΔT = change in temperature (in °C)

In this case, we know:
Q = 1140 joules
m = 30 grams
ΔT = 20 °C

Now we can rearrange the formula to solve for c:

c = Q / (m * ΔT)

Substituting the given values:

c = 1140 joules / (30 grams * 20 °C)

Now, let's perform the calculation:

c = 1140 joules / (600 grams °C)

The unit "grams°C" doesn't make mathematical sense, so we need to simplify the unit by converting grams to kilograms:

c = 1140 joules / (0.6 kilograms °C)

Finally, simplifying the equation gives us the specific heat of the plastic in the container:

c = 1900 joules/kilogram °C

Therefore, the specific heat of the plastic in the container is 1900 joules/kilogram °C.