posted by nikita on .
tori wants to increase the tempreature of 500 grams of water from 20 degrees celcius to 100 degrees celecius if the specific heat of water is 4.18j/g. degrees celcius how much heat is needed ?
same song, second verse. And celcius should be celsius.
Q=mxcx(temperature final-temperature initial) , next subtitute values; Q=500gx4.18J/g*Cx(100-20)*C, then cross out g with g and *C with *C . Multiply 500x4.18J ,and subtract 100-20 like this q=500x4.18Jx80=2090x80=167200J . Round to the significant figure will be 167J, that is how much heat is needed. I hope tis can help.