Posted by **RD** on Tuesday, March 1, 2011 at 12:54pm.

A bullet of mass 3.2 g strikes a ballistic pendulum of mass 3.6 kg. The center of mass of the pendulum rises a vertical distance of 13 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

- Physics -
**bobpursley**, Tuesday, March 1, 2011 at 1:39pm
you can only use conservation of momentum on the collision

Momentumbullet=momentumbullet/pendulum

.0032*Vi=3.6032*Vf

Now you can consider energy after the collision

1/2 (3.6032)Vf^2=(3.6032)*9.8*.13

in the second equation, solve for Vf, then put it in the first equation, and solve for Vi.

## Answer this Question

## Related Questions

- physics - A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The ...
- physics for physical science - a bullet of mass 0.015kg strikes ballistic ...
- Physics - A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. ...
- physics - a bullet of mass 0.015kg strikes a ballistic pendullum of mass 2kg.the...
- physics - A ballistic pendulum consists of a rectangular wooden block of mass 1....
- physics - A(n) 3.46 g bullet is fired into a(n) 2.4 kg ballistic pendulum and ...
- Physics - A(n) 5.52 g bullet is fired into a(n) 3.07 kg ballistic pendulum and ...
- mambane - A 10.0g bullet is fired with a speed of 500m/s into a pendulum block ...
- Physics - A ballistic pendulum was a device used in the past century to measure ...
- physics - A ballistic pendulum, as shown in the figure, was a device used in the...

More Related Questions