Friday

January 30, 2015

January 30, 2015

Posted by **RD** on Tuesday, March 1, 2011 at 12:54pm.

- Physics -
**bobpursley**, Tuesday, March 1, 2011 at 1:39pmyou can only use conservation of momentum on the collision

Momentumbullet=momentumbullet/pendulum

.0032*Vi=3.6032*Vf

Now you can consider energy after the collision

1/2 (3.6032)Vf^2=(3.6032)*9.8*.13

in the second equation, solve for Vf, then put it in the first equation, and solve for Vi.

**Answer this Question**

**Related Questions**

physics - A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The ...

physics for physical science - a bullet of mass 0.015kg strikes ballistic ...

Physics - A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. ...

physics - a bullet of mass 0.015kg strikes a ballistic pendullum of mass 2kg.the...

physics - A ballistic pendulum consists of a rectangular wooden block of mass 1....

physics - A ball of mass 0.075 kg is fired horizontally into a ballistic ...

physics - A ball of mass 0.075 kg is fired horizontally into a ballistic ...

physics - A(n) 3.46 g bullet is fired into a(n) 2.4 kg ballistic pendulum and ...

Physics - A(n) 5.52 g bullet is fired into a(n) 3.07 kg ballistic pendulum and ...

Physics - A ballistic pendulum was a device used in the past century to measure ...