Posted by **Mark** on Tuesday, March 1, 2011 at 2:54am.

Find the volume of the solid whose base is the region bounded between the curve y=sec x and the x-axis from x=pi/4 to x=pi/3 and whose cross sections taken perpendicular to the x-axis are squares.

## Answer This Question

## Related Questions

- calculus - the region bounded by the quarter circle (x^2) + (y^2) =1. Find the ...
- Calculus - Find the volume of the solid whose base is the region bounded by y=x^...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- calculus - The base of a solid is bounded by the curve y= sort (x+2) ,the x-axis...
- Calculus - Find the volume of the solid obtained by rotating the region bounded ...
- Calculus - Find the volume of the solid obtained by rotating the region bounded ...
- Calculus - Find the volume of the solid obtained by rotating the region bounded ...
- Calculus - The functions f and g are given by f(x)=√x and g(x)=6-x. Let R ...

More Related Questions