a rectangle has length which is twice the width. if the diagonal is the 5 times the square root of 5 meters long, find the perimeter of the rectangle.
L=Lenght
W=With
D=Diagonal
P=Perimeter
L=2W
D=sqroot(L^2+W^2)
D=sqroot[(2W)^2+W^2=5*sqroot(5)
sqroot(4W^2+W^2)=5*sqroot(5)
sqroot(5W^2)=5*sqroot(5)
sqroot(5)*W=5*sqroot(5)
Diwide booth sides with sqroot(5)
W=5
W=5m
L=2W
L=10
L=10m
P=2L+2W=2(L+W)=2*(5+10)=2*15=30
P=30m