Homework Help: physics

Posted by polo Q on Monday, February 28, 2011 at 11:33pm.

The force exerted by the wind on the sails of a sailboat is 500 N north. The water exerts a force of 150 N east. If the boat (including its crew) has a mass of 290 kg, what are the magnitude and direction of its acceleration?

physics - Ariel @NSU, Monday, March 21, 2011 at 6:29pm
Magnitude = pythagorean theorem (net force)
F^2=(500^2)+(150^2)=272500
F=square root(272500)
F=522 N *answer*
Acceleration:
a (m/s^2)= F/m= (522N/290Kg)
a=1.8 m/s^2 *answer*

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