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August 28, 2014

August 28, 2014

Posted by **Marie** on Monday, February 28, 2011 at 11:02pm.

x/x+1 + 5/x = 1/x^2+x

also how do you write

(x-5)(x-5) would it be x^2-5

- Algebra 2 -
**Helper**, Tuesday, March 1, 2011 at 12:04amYou need parenthesis.

I'll assume your problem is,

x/(x+1) + 5/x = 1/(x^2 + x)

x/(x+1) + 5/x = 1/(x(x + 1))

Multiply both sides by x(x + 1)

x^2 + 5(x + 1) = 1

x^2 + 5x + 5 = 1

x^2 + 5x + 4 = 0

(x + 1)(x + 4) = 0

x = -1 or x = -4

Make sure you check both answers in the original equation. I have NOT checked.

- Algebra 2 -
**Paige**, Tuesday, March 1, 2011 at 12:14amI have been trying to figure this problem out and I am completely lost.

Could someone help guide me through it?

(3x^4-0x^3-8x^2 -3x-3) / (x^2-3)

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