Posted by **Mandy** on Monday, February 28, 2011 at 10:28pm.

By what amount does the sum of the roots exceed the product of the roots of the equation (x-7)(x+3)=0?

I have no idea what to do!

- Alg 2 -
**jai**, Tuesday, March 1, 2011 at 1:48am
first get the roots,,

(x-7)(x+3)=0

thus equating each term inside the parenthesis to zero,

x-7=0 and x+3=0

therefore, x=7 and x=-3

the roots are 7 and -3

sum: 7 + (-3) = 4

product: 7(-3) = -21

the questions asks for the difference between the sum and product, therefore:

4 - (-21) = 25

hope this helps~ :)

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