Alg 2
posted by Mandy on .
By what amount does the sum of the roots exceed the product of the roots of the equation (x7)(x+3)=0?
I have no idea what to do!

first get the roots,,
(x7)(x+3)=0
thus equating each term inside the parenthesis to zero,
x7=0 and x+3=0
therefore, x=7 and x=3
the roots are 7 and 3
sum: 7 + (3) = 4
product: 7(3) = 21
the questions asks for the difference between the sum and product, therefore:
4  (21) = 25
hope this helps~ :)