Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
We had to add 5.0 ml of pure acetic acide to the well and measure conductivity. Then we had to measure the conductivity of 0.01 M aqueous acetic acid. Explain what happens.
1 answer
Give details of your observations.
You can
ask a new question
or
answer this question
.
Similar Questions
Regarding conductivity:
1. If a solution has a high conductivity, it indicates that there are a lot of __________________ in
Top answer:
1. If a solution has a high conductivity, it indicates that there are a lot of __________________ in
Read more.
Prepare 500mL of a 0.200 M acetate buffer at pH 4.90 using only pure acetic acid, 3M NaOH, and water.
1) Add acetic acid to
Top answer:
To answer the first question and determine the amount of acetic acid needed, we need to use the
Read more.
The percentage composition of acetic acid with found to be 39.9% C,6.7%Hand 53.4%O, It is molar mass was determined by
Top answer:
Empirical Formula: CH2O Molecular Formula: C2H4O2
Read more.
mpare the four acetic acid and methanol conductivity measurements. What do they suggest about the bond that attaches the
Top answer:
The addition of H2O to the CH3COOH shows a relatively large increase in conductivity; hence the
Read more.
A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure
Top answer:
mass needed: 500ml*.08, and assuming the 8 percent is the same density as water, then that is 40
Read more.
A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure
Top answer:
8% m/v means 8 g acetic acid/100 mL soln. You want 500 mL soln so you want 5*8 = 40 g acetic acid.
Read more.
You are asked to prepare 500. mL of a 0.150 M acetate buffer at pH 5.00 using only pure acetic acid, 3.00 M NaOH, and water.
Top answer:
Well, well, well, it seems you're grappling with the complexities of buffer preparation. Don't
Read more.
I did an experiment on Buffers:
In a polystyrene beaker, mix 20 ml of 0.1M Acetic acid ad 25 ml of 0.1 M sodium acetate and
Top answer:
The equilibrium in both mixtures is: HC2H3O2(aq) <=> H+(aq) + C2H3O2^-(aq) For the first mixture use
Read more.
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a
Top answer:
Gms of HOAc = (35.0ml)(1.049g/ml) = 36.715gms HOAc moles HOAc = (36.715 g)/(60.05 g/mol) = 0.6114
Read more.
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a
Top answer:
density glacial acetic acid is 1.049 g/mL. How many grams acetic acid do we have in the 10.00 mL
Read more.
Related Questions
If the density of pure acetic acid is 1.005g/cm, what is it molarity
An electrician is trying to decide which kind of material to use to wire a house.
carbon steel: conductivity = 1.43 × 10−7,
If the density of pure acetic is 1.005g/cm3, what is it's molarity
If the density of pure acetic acid is 1.005g cm, what is its molarity?
An electrician is trying to decide which kind of material to use to wire a house.
⚫ carbon steel: conductivity = 1.43 x 10-7,
Wich statement correctly describes the conductivity of the specified material? Plastics have high conductivity. Gold has high
Which statement correctly describes the conductivity of the specified material?(1 point)
Aluminum has a low conductivity. Copper
Which statement correctly describes the conductivity of the specified material?(1 point)
Responses Plastics have high
A solution is 40% acetic acid by mass. The density of this solution is 1.049 g/mL. Calcu- late the mass of pure acetic acid in
Which statement correctly describes the conductivity of the specified material?(1 point)
Responses Plastics have high