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July 8, 2015

July 8, 2015

Posted by **Anonymus** on Monday, February 28, 2011 at 5:04pm.

- Math -
**Anonymous**, Monday, February 28, 2011 at 6:51pmRewrite equation:

tan^2(x)+6=sec^2(x)+5

6-5=sec^2(x)tan^2(x)

sec^2(x)-tan^2(x)=1

Now you must verify that:

sec^2(x)-tan^2(x)=1

tan(x)=sin(x)/cos(x)

tan(x)=sin(x)*sec(x)

tan^2(x)=sin^2(x)*sec^2(x)

sec^2(x)-tan^2(x)=

sec^2(x)-sin^2(x)*sec^2(x)=

sec^2(x)*[1-sin^2(x)]

sin^2(x)+cos^2(x)=1

cos^2(x)=1-sin^2(x)

sec^2(x)*[1-sin^2(x)]=

sec^2(x)*cos^2(x)

sec(x)=1/cos(x)

sec^2(x)=1/cos^2(x)

sec^2(x)*cos^2(x)=

[1/cos^2(x)]*cos^2(x)=1