Posted by Anonymous on Monday, February 28, 2011 at 2:42pm.
BOH ==> B^+ + OH^-
Convert pH of 10.72 to pOH, then convert pOH to OH^-. Set up an ICE chart for the above reaction and substitute into the Kb expression. Then solve for Kb.
Kb = (B^+)(OH^-)/(BOH)
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