the pH of a .3 M solution of a weak base is 10.72. what is the Kb of the base?
BOH ==> B^+ + OH^-
Convert pH of 10.72 to pOH, then convert pOH to OH^-. Set up an ICE chart for the above reaction and substitute into the Kb expression. Then solve for Kb.
Kb = (B^+)(OH^-)/(BOH)