Posted by bianca on Monday, February 28, 2011 at 1:39pm.
Graph the following equations; calculate the slope, xintercept, and yintercept, and label the intercepts on the graph.
Find the area of a rectangle if three of its corners are (0.1,3.4), (7.9,3.4), and (0.1,6.8).
one I draw the graph how do I figure out the area of the rectangle?

algebra  Helper, Monday, February 28, 2011 at 2:38pm
Find the area of a rectangle if three of its corners are (0.1,3.4), (7.9,3.4), and (0.1,6.8).
You are given 3 points of the rectangle.
You need to find the 4th point.
Rectangle ABCD, labeled clockwise from the bottom horizontal segment.
A(0.1, 3.4)
B(7.9, 3.4)
C(7.9, 6.8)
D(0.1, 6.8)
Point C was the missing point.
It has the same x coordinate as Point B and the same y coordinate as D.
A = LW
AB = CD = the horizontal segments, the length
BC = DA = the vertical segments, the width
Use the distance formula to find the segment lengths
Distance between AB
A(0.1, 3.4)
B(7.9, 3.4)
D(A,B)=sqrt[(xA  xB)^2 + (yA  yB)^2]
D = sqrt[(0.1+7.9)^2 + (3.4+3.4)^2]
D = 7.8
Distance between BC
B(7.9, 3.4)
C(7.9, 6.8)
D(A,B)=sqrt[(xA  xB)^2 + (yA  yB)^2]
D = sqrt[(7.9+7.9)^2 + (3.46.8)^2]
D = 10.2
A = LW
A = (7.8)(10.2)
A = ?
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