Posted by Anonymous on .
The gun, mount, and train car had a total mass of 1.22 106 kg. The gun fired a projectile that was 80.0 cm in diameter and weighed 7502 kg. In the firing illustrated in the figure, the gun has been elevated at è = 18.0° above the horizontal. If the railway gun was at rest before firing and moved to the right at a speed v = 4.53 m/s immediately after firing, what was the speed of the projectile as it left the barrel (muzzle velocity)?
it is not clear to me the figure, but conservation of momentum in the horizontal direction will work this out.
Use the equation M1V1=M2V2 where M1V1 is the momentum of the rail gun and M2V2 is the mass of the bullet and the horizontal component of its speed.