Homework Help: physics

Posted by heather on Monday, February 28, 2011 at 12:41pm.

A 2.48-kg rock is released from rest at a height of 28.1 m. Ignore air resistance and determine (a) the kinetic energy at 28.1 m, (b) the gravitational potential energy at 28.1 m, (c) the total mechanical energy at 28.1 m, (d) the kinetic energy at 0 m, (e) the gravitational potential energy at 0 m, and (f) the total mechanical energy at 0 m.

physics - James, Sunday, June 3, 2012 at 8:34pm
PE = m x g x h
PE = 2.48 x 9.8 x 28.1
PE = 682.94J at 28.1m
KE at 28.1m = 0, because the object is still at rest.
The kinetic energy at 0m transfers from the previously stated gravitational potential energy.
KE = 682.94J at 0m
Therefore PE = 0J at 0m
Mechanical energy is the sum of both KE and PE.

Answer this Question

Related Questions

physics - A 2.48-kg rock is released from rest at a height of 28.1 m. Ignore air...
physics - Please help me A 2 kg rock is released from rest at a height of 29 m. ...
physiscs - A 2 kg rock is released from rest at a height of 29 m. Ignore air ...
physics - A 2 kg rock is released from rest at a height of 29 m. Ignore air ...
College Physics - A 2.2 kg rock is released from rest at the surface of a pond 1...
College Physics - Part A) A 2.2 kg rock is released from rest at the surface of ...
physics - A 2.2 kg rock initially at rest loses 412 J of potential energy while ...
physics - A 48 kg skier starts from rest at a height of H = 28 m above the end ...
Physics - A rock of mass m and a rock of mass 2m are both released from rest at ...
physics - A 0.26 kg rock is thrown vertically upward from the top of a cliff ...

For Further Reading

First Name:
School Subject:
Answer: