Posted by **heather** on Monday, February 28, 2011 at 12:31pm.

A 0.582-kg basketball is dropped out of a window that is 5.98 m above the ground. The ball is caught by a person whose hands are 1.58 m above the ground. (a) How much work is done on the ball by its weight? What is the gravitational potential energy of the basketball, relative to the ground, when it is (b) released and (c) caught? (d) What is the change (PEf - PE0) in the ball's gravitational potential energy?

## Answer This Question

## Related Questions

- physics - A 0.582-kg basketball is dropped out of a window that is 5.98 m above ...
- physics - A 0.579 kg basketball is dropped out of a window that is 6.22 m above ...
- physics - A 0.579 kg basketball is dropped out of a window that is 6.22 m above ...
- physics - A 0.620 kg basketball is dropped out of a window that is 6.40 m above...
- Physics 1 - A 0.620 kg basketball is dropped out of a window that is 6.40 m ...
- physics - A 0.662-kg basketball is dropped out of a window that is 6.32 m above ...
- Physics 2 - A 0.564-kg basketball is dropped out of a window that is 5.85 m ...
- College Physics - A 0.697-kg basketball is dropped out of a window that is 6.98 ...
- Gen physics - A 0.662-kg basketball is dropped out of a window that is 6.32 m ...
- Physics - A 0.60-kg basketball is dropped out of the window that is 6.1 m above ...

More Related Questions