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Posted by **bianca** on Monday, February 28, 2011 at 11:46am.

Find an equation in slope-intercept form passing through the points (-6.2,18.1) and (-3.4,18.1).

- algbra -
**drwls**, Monday, February 28, 2011 at 12:11pmPart 1. We don't draw graphs here. You have not provided any equations, anyway.

Part 2. Both points have the same y value. You therefore have a horizontal line with equation y = 18.1

The slope is zero and the y-intercept is 18.2.

- algbra -
**bianca**, Monday, February 28, 2011 at 12:15pmhow would I do th equation on this problem?

- algbra -
**Helper**, Monday, February 28, 2011 at 1:21pmdrwls gave you the equation above.

"You therefore have a horizontal line with equation"

y = 18.1

points (-6.2,18.1) and (-3.4,18.1)

As drwls said above,

"The slope is zero and the y-intercept is 18.1."

The slope intercept form of an equation is,

y = mx + b

m = 0

y-intercept = 18.1

y = 0x + 18.1

y = 18.1 is the equation for the line.

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