Posted by Mk on Monday, February 28, 2011 at 3:16am.
write the equation of the circle that satisfies each set of conditions.
the center of the circle is on the xaxis, its radius is 1, and it passes through the point (square root of 2 over 2, square root of two over 2)

Advanced Math  agrin04, Monday, February 28, 2011 at 5:52am
Circle equation generally:
(xa)^2 + (yb)^2 = r^2
The center is in xaxis (b = 0), giving:
(xa)^2 + y^2 = 1
((sqrt(2)/2)a)^2 + (sqrt(2)/2)^2 = 1
((sqrt(2)/2)a)^2 + (1/2) = 1
(sqrt(2)/2)a = Âħsqrt(1/2)
(sqrt(2)/2)a = sqrt(1/2)
a = 0
So: x^2 + y^2 = 1
(sqrt(2)/2)a = sqrt(1/2)
a = sqrt(2)
So: (xsqrt(2))^2 + y^2 = 1
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