Advanced Math
posted by Mk on .
write the equation of the circle that satisfies each set of conditions.
the center of the circle is on the xaxis, its radius is 1, and it passes through the point (square root of 2 over 2, square root of two over 2)

Circle equation generally:
(xa)^2 + (yb)^2 = r^2
The center is in xaxis (b = 0), giving:
(xa)^2 + y^2 = 1
((sqrt(2)/2)a)^2 + (sqrt(2)/2)^2 = 1
((sqrt(2)/2)a)^2 + (1/2) = 1
(sqrt(2)/2)a = Âħsqrt(1/2)
(sqrt(2)/2)a = sqrt(1/2)
a = 0
So: x^2 + y^2 = 1
(sqrt(2)/2)a = sqrt(1/2)
a = sqrt(2)
So: (xsqrt(2))^2 + y^2 = 1