Posted by **Mk** on Monday, February 28, 2011 at 3:16am.

write the equation of the circle that satisfies each set of conditions.

the center of the circle is on the x-axis, its radius is 1, and it passes through the point (square root of 2 over 2, square root of two over 2)

- Advanced Math -
**agrin04**, Monday, February 28, 2011 at 5:52am
Circle equation generally:

(x-a)^2 + (y-b)^2 = r^2

The center is in x-axis (b = 0), giving:

(x-a)^2 + y^2 = 1

((sqrt(2)/2)-a)^2 + (sqrt(2)/2)^2 = 1

((sqrt(2)/2)-a)^2 + (1/2) = 1

(sqrt(2)/2)-a = ħsqrt(1/2)

(sqrt(2)/2)-a = sqrt(1/2)

a = 0

So: x^2 + y^2 = 1

(sqrt(2)/2)-a = -sqrt(1/2)

a = sqrt(2)

So: (x-sqrt(2))^2 + y^2 = 1

## Answer this Question

## Related Questions

Advanced Math - Write the standard form of the equation of a circle that passes ...

NEED MAJOR HELP! *QUADRATIC EQUATIONS* - Write the equation for the circle with ...

Equations of a Circle - Write the standard for of the equation of the circle ...

Math - Find the equation of the circle that satisfies the given conditions. ...

maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...

math - -a circle with center at the point O(0,0) also has the point P(-2,3) on ...

math - a circle is tangent to the y-axis at y=3 and has one x-intercept at x=1 a...

Math - Write the standard for of the equation of the circle that passes through ...

Algebra - Knowing the given conditions, write the equation of the circle. Center...

math - how do i write this equation... circle with center (1,-3) that passes ...