Chem. Percent Yield
posted by Toni Jones on .
Titanium, a strong, lightweight metal used in many applications, is prepared by the reaction of titanium(IV) chloride with molten magnesium metal. 3.45 x 10^7g of titanium(IV) chloride is reacted with 1.13 x 10^7g of magnesium, 7.91 x 10^6g of titanium metal are obtained. What is the percent yield of the reaction?
This is a limiting reagent problem as well as a percent yield.
Write the balance equation.
Convert grams TiCl4 to moles. moles = grams/molar mass.
Do the same for Mg.
Using the coefficients in the balanced equation, convert moles of TiCl4 to moles of the product. Do the same for moles Mg. In is probably that the answer for moles Mg produced by the two procedures is not the same. In limiting regent problems the correct answer is ALWAYS the smaller value and the reagent producing that value is the limiting reagent. Convert the smaller value to grams by g = mols x molar mass.
Now percent yield = (g Ti produced/g Ti calculated above)*100.