Posted by **Anonymous** on Sunday, February 27, 2011 at 11:38pm.

consider a point on a circle x2+y2=1.At what rate Y is changing with respect to X when the point is at X=1/2....

- calculus -
**drwls**, Monday, February 28, 2011 at 4:06am
There are two points on the circle with x = 1/2:

(1/2, sqrt3/2) and (1/2,-sqrt3/2)

Which one are you talking about?

Anyway, what you want is dy/dx.

Use a ^ sign before exponents.

x^2 + y^2 = 1

Use implicit differentiation.

2x + 2y*dy/dx = 0

dy/dx = -x/y = -1/sqrt3 or 1/sqrt3

depending upon which of the two points you are talking about.

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